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Logarithm of a power
loga (xn) = n loga x
Explanation
From the logarithm of a product follows that
loga (xn) = loga (x · x · x ··· x) = loga x + loga x + ··· + loga x = n loga x
Example 1
You can see that ln (e2) = 2, because
ln (e2) = 2 ln (e) = 2
Example2
You can see that ln (√a) = ½ ln (a), because